Question 523004
Time  in I leg + time in II leg= 22

let the I leg be x
II leg = 500-x

t=d/r

x/10 + (500-x)/50= 22

LCD = 50 
multiply equation by 50
5x+500-x=1100

4x=600
x=150 m

150 m at 10m/s
350 m at 50m/s