Question 52058
Calling a number 2n + 1, where n is any integer guarantees
that 2n + 1 will be odd
Call the 3 successive odd integers
{{{2n + 1}}},{{{2n + 3}}},{{{2n + 5}}}
{{{3*(2n + 3) = 7 + (2n + 1) + (2n + 5)}}}
{{{6n + 9 = 7 + 4n + 6}}}
{{{2n = 13 - 9}}}
{{{2n = 4}}}
{{{n = 2}}}
{{{2n + 1 = 5}}}
{{{2n + 3 = 7}}}
{{{2n + 5 = 9}}}
The 3 successive odd numbers are 5,7,9
check
{{{3*(2n + 3) = 7 + (2n + 1) + (2n + 5)}}}
{{{3*7 = 7 + 5 + 9}}}
{{{21 = 12 + 9}}}
{{{21 = 21}}}
OK