Question 52026
Let the original sides fo the square be xcm
Area of the square= x^2 cm^2
When the sides are decreased by 3cm, then the area is (x-3)^2 sq cm
Given:
x^2-(x-3)^2=81
x^2-(x^2-6x+9)=81
x^2-x^2+6x-9=81
6x=81+9=90
x=15
So, the original dimensions of the square=15cm