Question 522553
Hypotenuse = 35
one leg x
other leg = x-7

Use Pythagoras theorem

x^2+(x-7)^2=35^2

x^2+x^2-14x+49=1225

2x^2-14x-1176=0
/2
x^2-7x-588=0

x^2-28x+21x-588=0
x(x-28)+21(x-28)=0
(x-28)(x+21)=0
take the positive value x=28 one leg
other leg = 21

21^2+28^2=1225

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