Question 519644
how do you graph y= a sin b(x+2pie)+d
**
Standard form of equation for graphing sin function: y=Asin(Bx-C), A=amplitude, Period=2π/B,
Phase-shift=C/B.
Rewrite given equation to standard form:
y=a sin(bx+b2π)+d
Steps for graphing:
1.Period=2π/b
1/4 perod=π/2b
2.Phase-shift=C/B=b2π/b=2π (shift to left)
3.Amplitude=a
4.vertical shift=d
5.On an (x,y) coordinate system, identify the (x,y) coordinates for the basic sin curve for given period, at each 1/4 period: (0,0), (π/2b,a), (π/b,0), (3π/2b,-a), (2π/b,0)
6.Shift the x-coordinates 2π units to the left.
7.For the final configuration, raise the y-coordinate d units vertically. This would make the maximum amplitude=a+d and minimum amplitude -a+d