Question 519991
Let csc &#952; = 19/6 , 0 < &#952; < pi/2 
sin&#952;= 6/19 Find: cos&#952;, tan&#952;, sec&#952;, and cot&#952;. 
How do you solve this?
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You are working in quadrant I where all the trig functions are>0
Given: 
opposite side=6
hypotenuse=19
adjacent side=&#8730;(19^2-6^2)=&#8730;325
Trig functions:
sin&#952;=6/19 (given)
cos&#952;=&#8730;325/19
tan&#952;=6/&#8730;325
csc&#952;=19/6
sec&#952;=19/&#8730;325
cot&#952;=&#8730;325/6