<PRE><B>Question 522263</B>
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If two numbers are in a 3:4 ratio, then there exists a constant of proportionality, *[tex \Large k], such that *[tex \Large 3k] is one of the numbers and *[tex \Large 4k] is the other number.  The sum is 35, so:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 3k\ +\ 4k\ =\ 35]


Solve for *[tex \Large k], then calculate *[tex \Large 3k] and *[tex \Large 4k] to find your two desired numbers.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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