Question 522149
	--------percent	----------------	quantity									
Alcohol Type I	20	----------------			650	ml						
Alcohol type II	90	----------------			x	ml						
Mixture	40	----------------	650	+	x	ml						
												
20*650+90x=40(650+x)
13000+90x=26000	+40x				
90x-40x	=26000-(	-13000)				
50x=13000									
/50											
x=	260										
260	ml		of			Alcohol type II	(90%)