<PRE><B>Question 522071</B>
*[tex \LARGE 3^x = 3^{x-1} + 7]


Rewrite *[tex \LARGE 3^x] as *[tex \LARGE 3(3^{x-1})]


*[tex \LARGE 3(3^{x-1}) = 3^{x-1} + 7]


*[tex \LARGE 2(3^{x-1}) = 7]


*[tex \LARGE 3^{x-1} = \frac{7}{2}], take log of both sides.


*[tex \LARGE x-1 = \log_3 \frac{7}{2} = \log_3 7 - \log_3 2]


*[tex \LARGE x = \log_3 7 - \log_3 2 - 1]</PRE>