Question 522070
base =b
height = 3b+2

1/2 * b*(3b+2)=28
b(3b+2)=28*2
3b^2+2b=56
3b^2+2b-56=0

Find the roots of the equation by quadratic formula						
						
a=	3	,b=	2	,c=	-56	
						
b^2-4ac=	4	+	672			
b^2-4ac=	676					
{{{x=(-b+-sqrt(b^2-4ac))/(2a)}}}						
{{{x1=(-b+sqrt(b^2-4ac))/(2a)}}}						
{{{x1=(-12+21)/(12)}}}						
x1=(	-2	+	26	)/	6	
x1=	4					
x2=(	-2	-26	) /	6		
x2= 	-4.67					
Ignore negative value	

base =4 and height = 3b+2 = 14