<PRE><B>Question 519875</B>
Find the equation of a line perpendicular to 4x-3y=12 that passes through the point (2,3)
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Standard form of equation for a straight line: y=mx+b, m=slope, b= y-intercept
For given equation:
4x-3y=12
-3y=-4x+12
divide by -3
y=4x/3-3
slope=4/3
..
For line perpendicular to given equation, slope=-3/4 (negative reciprocal)
Equation: y=-3x/4+b
Solving for b using coordinates of given point (2,3)
3=-3*2/4+b
b=3+6/4=36/12+18/12=54/12=9/2
equation: y=-3x/4+9/2</PRE>