Question 521915
let d be the number of dimes and q the number of quarters he has.

So, Steve has $(0.1d + 0.25q)= $4.10
the number of dimes he has is 8 fewer than the number of quarters.
so, d=q-8

from the two equations below, we have the following system:
         0.25q + 0.1d= 4.10
              q - d = 8
  
     by adding up the first equation and  0.1 time the second equation, we have

   0.25q + 0.1d + 0.1q - 0.1d = 4.10 + 0.1*8
  0.35q= 4.9
   q = 4.9/0.35
     = 14

   d = q - 8
     = 14 - 8
     = 6

so, Steve has 14 quarters and 6 dimes.