Question 521688
Two trains are 5000 feet apart, heading toward each other, but on separate parallel straight tracks,
 Train A is traveling at 45 miles per hour and Train B is traveling at 24 miles per hour.
Change 45 miles per hour and 24 miles per hour into feet per second.
45 mph: {{{(45*5280)/3600}}} = 66.0 ft/s
24 mph: {{{(24*5280)/3600}}} = 35.2 ft/s
:
Let t = time (in sec) for them to meet, write a distance eq: dist = speed*time
66t + 35.2t = 5000
101.2t = 5000
t = {{{5000/101.2}}}
t = 49.41 seconds
:
About how far will each train travel before they meet? Round your answers to the nearest hundredth.
45 mph train: 49.41 * 66 = 3261.06 ft
24 mph train: 49.41* 35.2= 1739.23 ft
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confirm this by adding:  5000.29 ~ 5000
:
In how many seconds will the trains meet? Like we said: 49.41 sec