Question 521871
The sum of two numbers is five times their difference. If one number exceeds the other by 7, find the numbers. 
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Equations:
x+y = 5(x-y)
x = y + 7
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Substitute for "x" and solve for "y":
y+7+y = 5(y+7-y)
2y + 7 = 35
2y = 28
y = 14 (one of the numbers)
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Solve for "x":
x = y + 7
x = 14+7
x = 21 (the other number)
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Cheers,
Stan H.
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