Question 521502
The ancient one is 40 years older than the youngster. 10 years agos, the age of the ancient one was 22 years greater than seven times the age of youngster then. How old are both of them today?
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Equations:
a = y + 40
(a-10) = 5y+22
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Substitute for "a" and solve for "y":
(y+40-10) = 5y+22
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y + 30 = 5y + 22
4y = 8
y = 2 yrs old (the younster's age now)
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Solve for "a":
a = y + 40
a = 2+40 = 42 yrs old (the ancient's age now)
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Cheers,
Stan H.
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