Question 51917
x+(x+2)+(x+4) are the three consecutive intergers then

3[(x+2)-(x+4)]=x+11 or 3(x+2-x-4)=x+11 or-6=x+11 or x=-17 

-17,-15,-13 Proof 3[-15-(-13)]=-17+11 or 3[-15+13]=-6 or 3*-2=- or -6=-6