Question 51906
This is the equation of a circle written in standard form:
(x-h)^2+(y-k)^2=r^2 where (h,k) is the center and r is the radius.
(x-2)^2+(y+3)^2=25  so (2,-3) is the center and 5 is the radius.
{{{graph(300,200,-15,15,-10,10,sqrt(25-(x-2)^2)-3,-sqrt(25-(x-2)^2)-3)}}}