Question 521058
The equation y = 0.5x - .01x^2 represents the parabolic flight of a certain cannonball shot at an angle of 26 degrees with the horizon and an initial velocity of 25 meters per second. In this equation, y is the height of the cannonball, in meters, and the x is the vertical distance traveled, in meters. 
First, Given the points (10,4) abd (40,0) lie on the parabola, at what x-coordinate must the vertex lie?
- I figured out that it is 25 meters because y = -0.01x^2 + 0.5x. a= -0.01 and b= 0.5. The I plugged it into -b/2a and got x=25. 
Secondly, use the equation and your answer to part one to find the maximum heigth of the baseball. 
- I plugged it into the equation of y = -0.01x^2 + 0.5x. It looked like this 
y = -0.01(25)^2 + 0.5(25)
y= 6.25 
Now, it says to use the point (0,0) and the location of the vertex to find the total horizontal distance that the baseball will travel. Im not sure how to find that.
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If the cannonball starts at (0,0) and has gone a horizontal distance of 25
by the time it reaches its vertex, it will go another 25 by the time
it hits the ground.
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Cheers,
Stan H.
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