Question 520964
<font face="Times New Roman" size="+2">


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \left(x\ -\ h\right)^2\ +\ \left(y\ -\ k\right)^2\ =\ r^2]


is a circle centered at *[tex \Large \left(h,\,k\right)] with radius *[tex \Large r]


Hint, re-write your equation:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \left(x\ -\ 3\right)^2\ +\ \left(y\ -\ 0\right)^2\ =\ 6^2]
 


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
<div style="text-align:center"><a href="http://outcampaign.org/" target="_blank"><img src="http://cdn.cloudfiles.mosso.com/c116811/scarlet_A.png" border="0" alt="The Out Campaign: Scarlet Letter of Atheism" width="143" height="122" /></a></div>
</font>