<PRE><B>Question 520838</B>
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&lt;b&gt;Step 1.&lt;/b&gt;  Determine the slope of the graph of your given equation.  The given equation is presented in slope-intercept form, so the slope of the graph is the coefficient on *[tex \Large x].


&lt;b&gt;Step 2.&lt;/b&gt;  Calculate the slope of the desired line.  Perpendicular lines have slopes that are negative (or opposite, if you prefer) reciprocals, that is:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  L_1\ \perp\ L_2 \ \ \Leftrightarrow\ \ m_1\ =\ -\frac{1}{m_2}\ \text{ and } m_1,\, m_2\, \neq\, 0]


&lt;b&gt;Step 3.&lt;/b&gt;  Use the point-slope form of an equation of a line to derive the desired equation:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ -\ y_1\ =\ m(x\ -\ x_1) ]


where *[tex \Large \left(x_1,y_1\right)] are the coordinates of the given point and *[tex \Large m] is the calculated slope.


&lt;b&gt;Step 4.&lt;/b&gt;  Determine the form of the answer desired by either your textbook or instructor/teacher/professor and arrange your point-slope form to the desired form.


You might also want to share with your instructor/teacher/professor that the question posed is grammatically and technically incorrect.  You cannot derive &lt;i&gt;the&lt;/i&gt; equation of a line.  You can only derive &lt;i&gt;an&lt;/i&gt; equation of a line.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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