Question 520513
Let the first number be x, then the next two consecutive numbers can be represented by x+1 and x+2. Now we know that x +(x+1)+(x+2) = 5961

Simplifying the left side we get 3x+3=5961

then 3x = 5958
 x = 1986.

Therefore the 3 consecutive numbers are 1986, 1987, and 1988.