Question 520166
{{{root(3,(x^3+8)/(x^2-4))=root(3,(x^3+2^3)/(x^2-2^2))=root(3,(x+2)(x^2-2x+4)/((x-2)(x+2)))=root(3,(x^2-2x+4)/(x-2))}}}
Formula {{{a^3+b^3=(a+b)(a^2-ab+b^2)}}}
{{{a^2-b^2=(a-b)(a+b)}}}