Question 520167
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Distance equals rate times time, so you can also say that time equals distance divided by rate.  Since the upstream trip is against the current, the upstream rate is the still water rate MINUS the current rate, and the downstream rate is the still water rate PLUS the current rate.  Let *[tex \Large r_c] represent the rate of the current and then the following two expressions are equal because the time for the upstream trip is the same as the time for the downstream trip.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{6}{6\ -\ r_c}\ =\ \frac{18}{6\ +\ r_c}]


Cross multiply and then solve for *[tex \Large r_c].  Doesn't matter what the dog's name is either; the answer is the same.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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