<PRE><B>Question 520170</B>
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2 is the first one, then 20 through 29 are the next 10, then 200 through 299 are the next 100, then 2000 through 2999 are the next 1000.  1 + 10 + 100 + 1000 = 1111. 1978 minus 1111 is 867, so we need 867 more:  20000 through 20866 (only 866 because of zero based count)


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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