Question 520104
x1		y1	x2	y2				
0		-6	1	1				
								
slope m =		(y2-y1)/(x2-x1)						
(	1	-	-6	)/(	1	-	0	) 
(	7	/	1	)  				
m=		7      						 

slope of line perpendicular will be negative reciprocal of 7

-1/7

m=		-  1/ 7					
							
Plug value of  the slope  and point 			(	5	,	8	) in
Y 	=	m	x 	+	b		
8.00	=	- 5/7	+	b			
b=	8	-	- 5/7				
b=	8  5/ 7						
So the equation  will be							
Y 	=	- 1/7	x 	+	61/7		
m.ananth@hotmail.ca