Question 519912
y^2+15y=2

y^2+15y-2=0

Find the roots of the equation by quadratic formula					
					
a=	1	,b=	15	,c=	-2
					
b^2-4ac=	225	+	8		
b^2-4ac=	233				
{{{x=(-b+-sqrt(b^2-4ac))/(2a)}}}					
{{{x1=(-b+sqrt(b^2-4ac))/(2a)}}}					
{{{x1=(-12+21)/(2)}}}					
x1=(	-15	+	15.26	)/	2
x1=	0.13				
x2=(	-15	-15.26	) /	2	
x2= 	-15.13				
 (0.13 Or -15.13)

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