<PRE><B>Question 519885</B>
i dont understand how to write an equation for the line that is parallel to 
y=(4/3)x-7 ; and contains given point, (7,2).
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The given line has a slope of m = 4/3
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Any line parallel to it must have slope = 4/3.
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Form of the Equation: 
y = mx + b
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You know y = 2 when x = 7 and the slope is 4/3.
Solve for &quot;b&quot;:
2 = (4/3)*7 + b
2 = 38/3 + b
b = 6/3-38/3
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b = -32/3
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Equation:
y = (4/3)x -(32/3)
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Cheers,
Stan H.
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