Question 519884
alice is 4 years younger than her husband, and twice as old now as she was 17 years ago. how old are they?
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Equations:
a = h-4
a = 2*17 = 34
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Substitute for "a" and solve for "h":
34 = h-4
husband's age = 34+4 = 38 yrs of age
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Cheers,
Stan H.
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