<PRE><B>Question 519623</B>
Sharon and Rae are riding bicycles on the same trail in the same direction, shareon crosses a bridge at 12:18 pm, Rae crosses the same bridge at 12:33pm,
 If sharon is going 8mph and Rae is going 10mph, when will Rae catch up with sharon?
:
From the information given, we know that R is 15 min behind S, at 12:18 PM
convert 15 min to .25 hrs
Find the distance R is behind S at this time: .25(10) = 2.5 mi
:
let t = time in hrs, that R catches s
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Write a distance equation; dist = speed * time
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10t = 8t + 2.5
10t - 8t = 2.5
2t = 2.5
t = 2.5/2
t = 1.25 hrs, which is 1 hr 15 min
:
Find the time from 12:18 PM: 12:18 + 1:15 = 13:33, or 1:33 PM, R catches S
:
:
Check this by finding the distance each rode
10*1.25 = 12.5 mi distance traveled
8*1.25 = 10 mi + 2.5 mi head start: = 12.5</PRE>