Question 519391
let the number be x
x^2-(2x+5)=0

x^2-2x-5=0

Find the roots of the equation by quadratic formula						
						
a=	1	,b=	-2	,c=	-5	
						
b^2-4ac=	4	+	20			
b^2-4ac=	24					
{{{x=(-b+-sqrt(b^2-4ac))/(2a)}}}						
{{{x1=(-b+sqrt(b^2-4ac))/(2a)}}}						
{{{x1=(-12+21)/(12)}}}						
x1=(	2	+	4.9	)/	2	
x1=	3.45					
x2=(	2	-4.9	) /	2		
x2= 	-1.45					
Ignore negative value	
3.45 is the number

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