Question 519433
PARALLEL								
								
								
7	x	+	10	y  	=	-24		
Find the slope of this line 								
make y the subject								
10	y  	=	-7	x	+	-24		
Divide by 	10							
	y  	=	-0.7	x		-2.4		
Compare this equation with y=mx+b								
slope m =	-0.7	=>- 7/10				
The slope of a line parallel to the above line will be the same			m=	-7/10	,point	(	70	,	92	)	
Find b by plugging the values of m & the point in								
y=mx+b								
92	=	-49	+	b				
b=	141							
m=	-7/10							
Plug value of  the slope  and b	in y = mx +b			
The required equation is		y  =	-7/10	x	+	141


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PERPENDICULAR TO A LINE 							7	x	+	10	y  	=	-24			
Find the slope of this line 									
									
10	y  	=	-7	x	+	6			
Divide by 	10								
	y  	=	-7/10	x	+	3/5			
Compare this equation with y=mx+b									
slope m =	-7/10								
									
The slope of a line perpendicular to the above line will be the negative reciprocal									
m1*m2=-1									
The slope of the required line will be 10/7						
									
m=	10/7	,point	(	70	,	92	)		
Find b by plugging the values of m & the point in									
y=mx+b									
92	=	100.00	+	b					
b=	-8								
m=	10/7								
The required equation is y  	=	10/ 7	x -8      		
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