Question 519457
The line passes through (4,-7) and is perpendicular to the line whose equation is x - 2y = 3. 
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First, determine slope of:
x - 2y = 3
-2y = -x + 3
2y = x - 3
y = (1/2)x - 3/2
slope is 1/2
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Slope of new line is negative reciprocal:
(1/2)m = -1
m = -2
slope if new line -2
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plug given point (4,-7) and slope (-2) into "point-slope" form:
y - y1 = m(x - x1)
y - (-7) = -2(x - 4)
y + 7 = -2x + 8
y = -2x + 1 (this is what they're looking for in "slope-intercept" form)