<PRE><B>Question 518661</B>
an airplane takes off at a 12 degree angle and travels at a rate of 240ft/sec. how long does it take for the plane to reach an altitude of 10000 ft?
:
We can solve this as a right triangle, the path of the plane is the hypotenuse (p)
the height is the side opposite the angle of 12 degrees, use the sine
Sine(12) = {{{10000/p}}}
.2079p = 10000
p = {{{1000/.2079}}}
p = 48,097.34 ft
Find the the time to travel this distance at 240 ft/sec
t = {{{48097.34/240}}}
t = 200.4 seconds, 3 min 20.4 sec to reach an altitude of 10000 ft
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