Question 518534
(x+1)/(x-3) < 5
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x cannot be 3 as the left side of the inequality would be undefined.
Solve the EQUALITY: x+1 = 5x-15 ; 4x = 16 ; x = 4
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Draw a Number line; plot x = 3  and x = 4 on the line.
Test a value in each of the three line intervals  to 
find the solution intervals.
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If x = 0 you get (0+1)/(0-3) <5 ; 
true so solutions in the interval (-oo,3)
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If x = 3.5 you get (3.5+1)/(3.5-3)<5 ; false
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If x = 5 you get (5+1)/(5-3) < 5 ; true so solutions in (4,+oo)
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Solution: (-oo,3)U(4,+oo)
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Cheers,
Stan H.
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