Question 518395
let the two digits be x and y then the no is 10x+y 
x=y+4 .......eqn(1)  and x+y= 1/5(10x+5) - 5 ........eqn(2)
from eqn(2) we obtain 5x-4y=25 ........eqn(3)
solving eqn(1) and eqn(2) simultaneouly yields
x=9 and y=5. Thus the no is 10(9)+5=95.