<PRE><B>Question 518197</B>
Through a mix-up on the production line, 6 defective refrigerators were shipped out with 54 good ones. 
If 5 are selected at random, what is the probability that all 5 are defective? Round your answer to 6 decimal places.

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Binomial Problem with n = 5 and p(defective) = 6/60 = 1/10
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P(5 of 5 are defective) = (1/10)^5 = 0.00001
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Cheers,
Stan H.
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