Question 518134
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Let *[tex \Large x] represent one of the numbers and let *[tex \Large y] represent the other.


Then the sum of the reciprocals is:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{1}{x}\ +\ \frac{1}{y}]


Apply the common denominator:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{y\ +\ x}{xy}]


But the sum is 54 and the product is 100 so:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{54}{100}\ =\ 0.54]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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