Question 517745
Start with the formula for the area of a rectangle:
{{{A = L*W}}}
But the length, L, is given as:
{{{L = 3W-2}}} "...length is 2ft. less than three times its width." Substitute this into the area formula.
{{{A = (3W-2)*W}}} Simplify.
{{{highlight(A = 3W^2-2W)}}} This is the function you need.
When the width is 2ft., then W = 2, so substitute.
{{{A = 3(2)^2-2(2)}}}
{{{A = 12-4}}}
{{{A = 8}}}
So when the width is 2ft., the area is 8sq.ft.