Question 517559
Age_Word_Problems/517559: Please answer this..ASAP.Thanks..a man is four years older than his wife and 5 times as old as his son.when the so was born,the age of the wife is six-seventh that of her husband's age. Find the age of the wife..
1 solutions


Let wife’s age be W
Then man’s age = W + 4
S, or son’s age = {{{1/5}}} man’s age, or {{{(1/5)(W + 4)}}}, or {{{(W + 4)/5}}}


{{{W - S = (6/7)(W + 4 - S)}}}


{{{W - (W + 4)/5 = (6/7) * W + 4 - ((W + 4))/5}}}


{{{W - (W + 4)/5 = (6/7) ((5W + 20 - W - 4)/5)}}}


35W – 7(W + 4) = 6(5W + 20 – W – 4) -------- Multiplying by LCD, 35


35W – 7W – 28 = 30W + 120 – 6W – 24


28W – 24W = 96 + 28


4W = 124


W, or wife’s age = {{{124/4}}}, or {{{highlight_green(31)}}}


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