Question 517550
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Presuming the typical convention of *[tex \Large l\ >\ w], we can write:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{l}{w}\ =\ \frac{5}{4}]


From which we derive:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ l\ =\ \frac{5w}{4}]


Then using the formula for the perimeter:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ P\ =\ 2l\ +\ 2w]


and substituting known values:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 2\left(\frac{5w}{4}\right)\ +\ 2w\ =\ 126]


Solve for *[tex \Large w], then calculate *[tex \Large \frac{5w}{4}]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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