Question 51682
  
   {{{4^(2/3)6^(2/3)9^(2/3)}}}
 = {{{3rd sqrt(4^2)*3rd sqrt(6^2)*3rd sqrt(9^2)}}}
 = {{{3rd sqrt(16)*3rd sqrt(36)*3rd sqrt(81)}}}
 = 3rd {{{sqrt(16*36*81)}}}
 = 3rd {{{sqrt(46656)}}}  =  3rd{{{sqrt(27*27*64)}}}  = 3rd{{{sqrt(3^3*3^3*4^3)}}}
 = 3 * 3 * 4  = 36. Answer.   I hope this must have solved your trouble in getting the answer.  

Note:  Read 3rd as 3rd root in the above solution.
  

gsm