Question 517404
You can think of this as one car standing still
and the other moving at the sum of their speeds.
I'll say the 50 mi/hr car is standing still.
{{{ d = r*t}}}
{{{ 333 = ( 60 + 50 )*t }}}
{{{ 333 = 110t }}}
{{{ t = 333/110 }}}
{{{ t = 3.0273 }}} hrs
10 AM + 3hrs = 1 PM
{{{ .0273*60 = 1.636 }}}
{{{ .636*60 = 38 }}}
They will be 333 mi apart at 1:01:38 PM