<PRE><B>Question 517045</B>
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Time equals distance divided by rate.  With the wind, the wind speed adds, against the wind, the wind speed subtracts.  Hence:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{2500}{450\ +\ r_w}\ =\ \frac{1900}{450\ -\ r_w}]


Solve for *[tex \Large r_w]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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