Question 517004
To solve this equation you need to write equations using what you know.  First, you know that the numbers are 3 consecutive even integers.  So A is your first, B = A + 2 and C = B + 2.
Next, you know that the sum of the second and third numbers is 20 more than the first: B + C = 20 + A.
Now plug the first two equations into the second, for B and C:
B + C = 20 + A
(A + 2) + (B + 2) = 20 + A
A + 2 + B + 2 = 20 + A
A + B + 4 = 20 + A
B + 4 = 20
B = 16
So the three consecutive even numbers are 14, 16, 18.