Question 516955

To solve this problem you need to set up two equations using what you know. First, you know the length of the rectangle is 5 more than the width: L = 5 + W.  Second, you know the perimeter of the rectangle is 6 times the width: L + L + W + W = 6W, or 2L + 2W = 6W.
Now plug in the first equation into the second equation, substituting the L with the (5 + w):
2L + 2W = 6W
2(5 + W) + 2W = 6W
10 + 2W + 2W = 6W
10 + 4W = 6W
10 = 2W
5 = W
So the width is 5.  Now plug that into the first equation:
L = 5 + W
L = 5 + 5
L = 10.  So using the length and width you can find the perimeter:
2L + 2W = P
2(10) + 2(5) = P
20 + 10 = P
30 = P.  The perimeter is 30.