Question 516749
Two numbers:  x & y.
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x - y = 20
so
x = y+20
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5x = 2y-4
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substitute
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5(y+20) = 2y-4
5y + 100 = 2y -4
3y + 100 = -4
3y = -104
y = -104/3
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x-y = 20
x-(-104/3) = 20
x + 104/3 = 20
x = 20 - 104/3
x = 60/3 -104/3
x = -44/3
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check to see if this works
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5x = 2y-4
5(-44/3) = -220/3
2y-4 = 2(-104/3) -4
2y-4 = -208/3 - 12/3 = -220/3
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Answer:  The numbers are -104/3 and -44/3.
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Done.