Question 516623
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Note that *[tex \Large x^2\ -\ 144] is the difference of two squares.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x^2\ -\ 144\ =\ 0]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ (x\ +\ 12)(x\ -\ 12)\ =\ 0]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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