Question 516433
A 40% solution of sulfuric acid is created by diluting a 25ml solution of 88% sulfuric acid with water.  How much water must be added to the 25ml 88% solution to obtain the 40% sulfuric acid solution?
.
Let x = amount (ml) of water added
then
.88(25) = .40(25+x)
22 = 10 + .40x
12 = .40x
30 ml = x