Question 516258
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Notice that we want to end up with 20 lbs of mix, half of which is raisins and the other half is a mix of nuts and M&Ms.  So the cost of the 10 lbs of raisins and the cost of the 10 lbs of nuts/M&Ms mix has to average (because the amounts are the same) to $3.79.


So the first question is "What is the cost of the nut/M&M mix that averages with $3.00/lb to make $3.79?  When you average two numbers, you add them together and divide by 2.  The result of that calculation was $3.79, so 2 times $3.79 is $7.58.  Subtract $3.00 to get $4.58 which must be the cost of the nut/M&M mix.  Like Dr. Livingstone said: Safari, so goodie.


Now, let *[tex \Large x] represent the number of lbs of peanuts required.  Then, since the peanuts and the M&Ms must weigh 10 lbs when all is said and done, *[tex \Large 10\ -\ x] must be the weight of the M&Ms.


The cost of *[tex \Large x] lbs of peanuts is then *[tex \Large 4x] dollars and the cost of *[tex \Large 10\ -\ x] lbs of M&Ms is then *[tex \Large 5(10\ -\ x)] dollars.  When you add up these two costs, you get 10 lbs times 4.58 per pound equals $45.80.  Symbolically:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 4x\ +\ 5(10\ -\ x)\ =\ 45.80]


All that you have to do now is solve for *[tex \Large x], the number of lbs of peanuts.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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