Question 515695
A tank contains 8000L of a solution that is 40%acid. How much water should be
added to make a solution that is 30% acid?
.
Let x = amount (liters) of water to add
then
.40(8000) = .30(8000+x)
3200 = 2400+.30x
800 = .30x
2666.67 liters = x